I want to write a function to return all the documents contained in mycollection in mongodb
from pymongo import MongoClient
if __name__ == '__main__': client = MongoClient("localhost", 27017, maxPoolSize=50) db=client.mydatabase collection=db['mycollection'] cursor = collection.find({}) for document in cursor: print(document)However, the function returns: Process finished with exit code 0
4 Answers
Here is the sample code which works fine when you run from command prompt.
from pymongo import MongoClient
if __name__ == '__main__': client = MongoClient("localhost", 27017, maxPoolSize=50) db = client.localhost collection = db['chain'] cursor = collection.find({}) for document in cursor: print(document)Please check the collection name.
4pymongo creates a cursor. Hence you'll get the object 'under' the cursor. To get all objects in general try:
list(db.collection.find({}))This will force the cursor to iterate over each object and put it in a list()
Have fun...
0I think this will work fine in your program.
cursor = db.mycollection # choosing the collection you need
for document in cursor.find(): print (document)it works fine for me,try checking the exact database name and collection name.
and try changing from db=client.mydatabase to db=client['mydatabase'] .
If your database name is such that using attribute style access won’t work (like test-database), you can use dictionary style access instead.source !
