How can I parse a JSON file with PHP? [duplicate]

I tried to parse a JSON file using PHP. But I am stuck now.

This is the content of my JSON file:

{ "John": { "status":"Wait" }, "Jennifer": { "status":"Active" }, "James": { "status":"Active", "age":56, "count":10, "progress":0.0029857, "bad":0 }
}

And this is what I have tried so far:

<?php
$string = file_get_contents("/home/michael/test.json");
$json_a = json_decode($string, true);
echo $json_a['John'][status];
echo $json_a['Jennifer'][status];

But because I don't know the names (like 'John', 'Jennifer') and all available keys and values (like 'age', 'count') beforehand, I think I need to create some foreach loop.

I would appreciate an example for this.

16 Answers

To iterate over a multidimensional array, you can use RecursiveArrayIterator

$jsonIterator = new RecursiveIteratorIterator( new RecursiveArrayIterator(json_decode($json, TRUE)), RecursiveIteratorIterator::SELF_FIRST);
foreach ($jsonIterator as $key => $val) { if(is_array($val)) { echo "$key:\n"; } else { echo "$key => $val\n"; }
}

Output:

John:
status => Wait
Jennifer:
status => Active
James:
status => Active
age => 56
count => 10
progress => 0.0029857
bad => 0

run on codepad

I can't believe so many people are posting answers without reading the JSON properly.

If you foreach iterate $json_a alone, you have an object of objects. Even if you pass in true as the second parameter, you have a two-dimensional array. If you're looping through the first dimension you can't just echo the second dimension like that. So this is wrong:

foreach ($json_a as $k => $v) { echo $k, ' : ', $v;
}

To echo the statuses of each person, try this:

<?php
$string = file_get_contents("/home/michael/test.json");
if ($string === false) { // deal with error...
}
$json_a = json_decode($string, true);
if ($json_a === null) { // deal with error...
}
foreach ($json_a as $person_name => $person_a) { echo $person_a['status'];
}
?>

The most elegant solution:

$shipments = json_decode(file_get_contents("shipments.js"), true);
print_r($shipments);

Remember that the json-file has to be encoded in UTF-8 without BOM. If the file has BOM, then json_decode will return NULL.

Alternatively:

$shipments = json_encode(json_decode(file_get_contents("shipments.js"), true));
echo $shipments;

Try

<?php
$string = file_get_contents("/home/michael/test.json");
$json_a = json_decode($string,true);
foreach ($json_a as $key => $value){ echo $key . ':' . $value;
}
?>

It's completely beyond me that no one pointed out that your begining "tags" are wrong. You're creating an object with {}, while you could create an array with [].

[ // <-- Note that I changed this { "name" : "john", // And moved the name here. "status":"Wait" }, { "name" : "Jennifer", "status":"Active" }, { "name" : "James", "status":"Active", "age":56, "count":10, "progress":0.0029857, "bad":0 }
] // <-- And this.

With this change, the json will be parsed as an array instead of an object. And with that array, you can do whatever you want, like loops etc.

Try This

 $json_data = '{ "John": { "status":"Wait" }, "Jennifer": { "status":"Active" }, "James": { "status":"Active", "age":56, "count":10, "progress":0.0029857, "bad":0 } }'; $decode_data = json_decode($json_data); foreach($decode_data as $key=>$value){ print_r($value); }

Try:

$string = file_get_contents("/home/michael/test.json");
$json = json_decode($string, true);
foreach ($json as $key => $value) { if (!is_array($value)) { echo $key . '=>' . $value . '<br />'; } else { foreach ($value as $key => $val) { echo $key . '=>' . $val . '<br />'; } }
}

More standard answer:

$jsondata = file_get_contents(PATH_TO_JSON_FILE."/jsonfile.json");
$array = json_decode($jsondata,true);
foreach($array as $k=>$val): echo '<b>Name: '.$k.'</b></br>'; $keys = array_keys($val); foreach($keys as $key): echo '&nbsp;'.ucfirst($key).' = '.$val[$key].'</br>'; endforeach;
endforeach;

And the output is:

Name: John Status = Wait
Name: Jennifer Status = Active
Name: James Status = Active Age = 56 Count = 10 Progress = 0.0029857 Bad = 0

Loop through the JSON with a foreach loop as key-value pairs. Do type-checking to determine if more looping needs to be done.

foreach($json_a as $key => $value) { echo $key; if (gettype($value) == "object") { foreach ($value as $key => $value) { # and so on } }
}

<?php
$json = '{ "response": { "data": [{"identifier": "Be Soft Drinker, Inc.", "entityName": "BusinessPartner"}], "status": 0, "totalRows": 83, "startRow": 0, "endRow": 82 }
}';
$json = json_decode($json, true);
//echo '<pre>'; print_r($json); exit;
echo $json['response']['data'][0]['identifier'];
$json['response']['data'][0]['entityName']
echo $json['response']['status'];
echo $json['response']['totalRows'];
echo $json['response']['startRow'];
echo $json['response']['endRow'];
?>

Try it:

foreach ($json_a as $key => $value) { echo $key, ' : '; foreach($value as $v) { echo $v." "; }
}

When you decode a json string, you will get an object. not an array. So the best way to see the structure you are getting, is to make a var_dump of the decode. (this var_dump can help you understand the structure, mainly in complex cases).

<?php $json = file_get_contents('/home/michael/test.json'); $json_a = json_decode($json); var_dump($json_a); // just to see the structure. It will help you for future cases echo "\n"; foreach($json_a as $row){ echo $row->status; echo "\n"; }
?>

$json_a = json_decode($string, TRUE);
$json_o = json_decode($string);
foreach($json_a as $person => $value)
{ foreach($value as $key => $personal) { echo $person. " with ".$key . " is ".$personal; echo "<br>"; }
}

The quickest way to echo all json values is using loop in loop, the first loop is going to get all the objects and the second one the values...

foreach($data as $object) { foreach($object as $value) { echo $value; } }

You have to give like this:

echo $json_a['John']['status'];
echo "<>"
echo $json_a['Jennifer']['status'];
br inside <>

Which gives the result :

wait
active

I am using below code for converting json to array in PHP, If JSON is valid then json_decode() works well, and will return an array, But in case of malformed JSON It will return NULL,

<?php
function jsonDecode1($json){ $arr = json_decode($json, true); return $arr;
}
// In case of malformed JSON, it will return NULL
var_dump( jsonDecode1($json) );
?>

If in case of malformed JSON, you are expecting only array, then you can use this function,

<?php
function jsonDecode2($json){ $arr = (array) json_decode($json, true); return $arr;
}
// In case of malformed JSON, it will return an empty array()
var_dump( jsonDecode2($json) );
?>

If in case of malformed JSON, you want to stop code execution, then you can use this function,

<?php
function jsonDecode3($json){ $arr = (array) json_decode($json, true); if(empty(json_last_error())){ return $arr; } else{ throw new ErrorException( json_last_error_msg() ); }
}
// In case of malformed JSON, Fatal error will be generated
var_dump( jsonDecode3($json) );
?>

Pop Glow

How can I parse a JSON file with PHP? [duplicate]

16 Answers

You Might Also Like

Will any Pokemon appear in a horde?

How do I efficiently lower my karma?

What is the difference between a texture pack and a shader?

Lost email to Steam