How to suppress a third-party warning using warnings.filterwarnings

I am using Paramiko in my python code (for sftp). Everything works fine except that everytime I import or call a paramiko function. This warning would show up:

C:\Python26\lib\site-packages\Crypto\Util\randpool.py:40: RandomPool_Deprecation
Warning: This application uses RandomPool, which is BROKEN in older releases. S
ee RandomPool_DeprecationWarning)

I know that this has to do with the fact that Paramiko is using some Deprecated functionalities of PyCrypto.

My question is, is there a way to suppress this warning programmatically ? I have tried this:

warnings.filterwarnings(action='ignore', \
category=DeprecationWarning, module='paramiko')

and even this:

warnings.filterwarnings(action='ignore', \
category=DeprecationWarning, module='randpool')

before 'import paramiko' statement and before paramiko-specific function calls, but nothing works. This warning keeps showing up no matter what. If it helps, here's the code in the third party library that prints the warning:

in randpool.py:

from Crypto.pct_warnings import RandomPool_DeprecationWarning
import Crypto.Random
import warnings
class RandomPool: """Deprecated. Use Random.new() instead. See """ def __init__(self, numbytes = 160, cipher=None, hash=None, file=None): warnings.warn("This application uses RandomPool, which is BROKEN in older releases. See ", RandomPool_DeprecationWarning)

If you know a way around this, please help me shut this warning off.

4 Answers

Easiest way would be as the warnings module suggests here:

with warnings.catch_warnings(): warnings.simplefilter("ignore") import paramiko

The module argument to warnings.filterwarnings takes a case-sensitive regular expression which should match the fully qualified module name, so

warnings.filterwarnings( action='ignore', category=DeprecationWarning, module=r'.*randpool'
)

or

warnings.filterwarnings( action='ignore', category=DeprecationWarning, module=r'Crypto\.Utils\.randpool'
)

should work. You may need to write RandomPool_DeprecationWarning explicitly instead of DeprecationWarning if for some reason RandomPool_DeprecationWarning is not a subclass of DeprecationWarning.

You can also disable the warning on the command line when you invoke the script by passing the -W option to the interpreter like so:

$ python -W ignore::RandomPool_DeprecationWarning:Crypto.Utils.randpool: my_script.py

The -W takes filters in the format action:message:category:module:lineno, where this time module must exactly match the (fully-qualified) module name where the warning is raised.

See and

To filter only a specific warning:

with warnings.catch_warnings(): warnings.simplefilter('ignore', SpecificWarningObject) #do something that raises a Warning

The most flexible way is to combine warnings.filterwarnings() (or warnings.simplefilter()) with the warnings.catch_warnings() context manager. This way you ge the flexibility of filterwarnings but the filtering is only applied inside the with block:

import warnings
with warnings.catch_warnings(): warnings.filterwarnings( action='ignore', category=SomeWarningClass, message='some message') # Do stuff that causes the warning

See The Warnings Filter in the docs for the descriptions of the arguments for filterwarnings.

Full example

Here is a full example with a custom warning:

import warnings
# Custom warning class for the example
class MyWarning(UserWarning): pass
def function_that_raises_warning(num): print(num) warnings.warn("This is a warning", MyWarning)
with warnings.catch_warnings(): function_that_raises_warning(1) # raises warning warnings.filterwarnings( action="ignore", category=MyWarning, message="This is a warning" ) function_that_raises_warning(2) # Warning is filtered
function_that_raises_warning(3) # raises warning

Example output

1
.\test_warnings.py:10: MyWarning: This is a warning warnings.warn("This is a warning", MyWarning)
2
3
.\test_warnings.py:10: MyWarning: This is a warning warnings.warn("This is a warning", MyWarning)