I'm trying to explore the Algorithmia image taggers in python.
client.algo("deeplearning/IllustrationTagger/0.2.5")
client.algo("deeplearning/InceptionNet/1.0.3")But that's not quite relevant to this question, as it applies to dictionaries in general.
for dict in dictList: print(dict)And this is the output:
//{'safe': 0.9950032234191896}
//{'questionable': 0.004409242421388626}
//{'explicit': 0.00011681715113809332}
I can access the key just fine:
for dict in dictList: for key in dict: print(key)//safe
//questionable
//explicit
But when I'm trying to unpack both the key and the value:
for dict in dictList: for key, value in dict: print(key) print(value)I get this error:
for key, value in dict:
ValueError: too many values to unpack (expected 2)
How can I access both the key and the value ?
EDIT: I've renamed obj and array to dict and list not to confuse with Javascript notation.
31 Answer
Like this - first:
for obj in objArray: for key in obj: value = obj[key] print(key) print(value)Second (python 3):
for obj in objArray: for key, value in obj.items(): print(key) print(value)For python 2 you can use for key, value in d.iteritems()