Ive tried looking on the internet and I can't seem to find any identities for $\arctan(x+y)$. I was wondering if anyone knows any?
Thanks!
$\endgroup$ 32 Answers
$\begingroup$The closest I know of is $$\arctan(x) + \arctan(y) = \arctan\left(\frac{x+y}{1-xy}\right)$$
(of course up to a multiple of $\pi$, and for $xy \neq 1$) Other than that I'm not aware of any useful ones.
Depending on what you want to achieve it might also be worth looking into Wikipedia:
$\endgroup$ $\begingroup$$$\arctan(x+y) + \arctan(x-y) = \arctan\left(\frac{2 x}{1-x^2+y^2}\right)$$
$$\arctan(x+y) - \arctan(x-y) = \arctan\left(\frac{2 y}{1+x^2-y^2}\right)$$
Taking sum
$$2 \arctan(x+y) = \arctan\left(\frac{2 x}{1-x^2+y^2}\right)+\arctan\left(\frac{2 y}{1+x^2-y^2}\right)$$
If $z= x+iy , u = $ real part of $ z^2 $
$$ 2 \arctan(x+y) = \arctan\left(\frac{2 x}{1-u}\right)+\arctan\left(\frac{2 y}{1+u}\right)$$
for whatever use it could be put to..
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