Printing chars and their ASCII-code in C

How do I print a char and its equivalent ASCII value in C?

1

8 Answers

This prints out all ASCII values:

int main()
{ int i; i=0; do { printf("%d %c \n",i,i); i++; } while(i<=255); return 0;
}

and this prints out the ASCII value for a given character:

int main()
{ int e; char ch; clrscr(); printf("\n Enter a character : "); scanf("%c",&ch); e=ch; printf("\n The ASCII value of the character is : %d",e); getch(); return 0;
}

8

Try this:

char c = 'a'; // or whatever your character is
printf("%c %d", c, c);

The %c is the format string for a single character, and %d for a digit/integer. By casting the char to an integer, you'll get the ascii value.

1

Nothing can be more simple than this

#include <stdio.h>
int main()
{ int i; for( i=0 ; i<=255 ; i++ ) /*ASCII values ranges from 0-255*/ { printf("ASCII value of character %c = %d\n", i, i); } return 0;
} 

Source: program to print ASCII value of all characters

To print all the ascii values from 0 to 255 using while loop.

#include<stdio.h>
int main(void)
{ int a; a = 0; while (a <= 255) { printf("%d = %c\n", a, a); a++; } return 0;
}

1

#include<stdio.h> void main()
{
char a;
scanf("%c",&a);
printf("%d",a);
}

Chars within single quote ('XXXXXX'), when printed as decimal should output its ASCII value.

int main(){ printf("D\n"); printf("The ASCII of D is %d\n",'D'); return 0;
}

Output:

% ./a.out
>> D
>> The ASCII of D is 68

This reads a line of text from standard input and prints out the characters in the line and their ASCII codes:

#include <stdio.h>
void printChars(void)
{ unsigned char line[80+1]; int i; // Read a text line if (fgets(line, 80, stdin) == NULL) return; // Print the line chars for (i = 0; line[i] != '\n'; i++) { int ch; ch = line[i]; printf("'%c' %3d 0x%02X\n", ch, ch, (unsigned)ch); }
}

2

Simplest approach in printing ASCII values of a given alphabet.

Here is an example :

#include<stdio.h>
int main()
{ //we are printing the ASCII value of 'a' char a ='a' printf("%d",a) return 0;
}